SOLUTION: Near the surface of a distant planet, the acceleration due to gravity is 26 feet per second squared (26ft over sec squared) express this using unit analysis in miles per square min
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Question 224482: Near the surface of a distant planet, the acceleration due to gravity is 26 feet per second squared (26ft over sec squared) express this using unit analysis in miles per square minute. Round answer to tenths place. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Near the surface of a distant planet, the acceleration due to gravity is 26 feet per second squared (26ft over sec squared) express this using unit analysis in miles per square minute. Round answer to tenths place.
:
26s^2
:
26 ft accelerated for 1 min
:
26(60^2) = 93,600 ft which is = 17.7 mi
:
17.7m^2
:
:
See if that is true, check using 2 min (120 sec)
26(120^2) = 374400 ft which is = 70.9 miles
and
17.7(2^2) = 70.8 miles, close enough
