Question 224476: Dara invested some money at 3% simple interest and $6000 more than that at 4.5% simple interest. After 1 year her total interest from the two accounts was $870. How much did she invest at each rate?
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! .03X+.045(X+6,000)=870
.03X+.045X+270=870
.075X=870-270
.075X=600
X=600/.075
X=8,000 AMOUNT INVESTED @ 3%.
8,000+6,000=14,000 AMOUNT INVESTED @ 4.5%.
PROOF:
.03*8,000+.045*14,000=870
240+630=870
870=870
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