SOLUTION: 2x-2y+z=31 3x+4y+z=1 x-3y-2z=10 I got (6,-6,7) Is that correct?
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-> SOLUTION: 2x-2y+z=31 3x+4y+z=1 x-3y-2z=10 I got (6,-6,7) Is that correct?
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Question 224278
:
2x-2y+z=31
3x+4y+z=1
x-3y-2z=10
I got (6,-6,7) Is that correct?
Answer by
Alan3354(69443)
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Yes, it is.
