SOLUTION: I just need to see how to solve the system: 2x-y=7 3x+2y=0 Thanks a bunch

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Question 22427: I just need to see how to solve the system: 2x-y=7 3x+2y=0
Thanks a bunch
Answer by NaiXLG(18) About Me  (Show Source):
You can put this solution on YOUR website!
So you want to solve the system;
+2x-y+=+7+
+3x+%2B+2y+=+0+

I'll show you an easy way called the substitution method....
In the first equation, solve for y.
+y+=+-7+%2B+2x+
Now, plug that into the second equation (now that you know what y equals);
+3x+%2B+2%28-7+%2B+2x%29+=+0+
Solve that equation for x;
+3x+-+14+%2B+4x+=+0+
+7x+-+14+=+0+
+7x+=+14+
+x+=+2+
Now, plug that x back into the first, equation that we solved for y in. +y+=+-7+%2B+2x+
+y+=+-7+%2B+2%282%29+
+y+=+-7+%2B+4+
+y+=+-3+
So the solution to the system is;
(x,y) = (2,-3)
*** that is where the two lines intersect.