Question 22415: Can anyone help?
Graph the parabola, locate vertex, axis of symmetry and intercepts.
g(x) = 2x^2 - 5x - 3
I tried:
[2x^2 - 5x + (5/2)^2] - 3 - (5/2)^2
(2x^2 - 5x + 25/4) - 3 - 25/4
(2x^2 - 5x + 25/4) - 37/4
or:
2x^2 - 5x - 3 = 0
divide both sides by two:
x^2 - 5/2x - 3/2 = 0
x^2 - 5/2x = 3/2
x^2 - 5/2x - 25/16 = 3/2 + 25/16
x^2 - 5/2x - 25/16 = 49/16
Can anyone help out?
Thanks!
Sandy
Answer by MORUPHOSUOLALE(24)  (Show Source):
You can put this solution on YOUR website! g(x)-- 2x^2-5x-3
vetex = (-b/2a), f(-b/2a)
-(-5/2(2)}
=5/4 =1.25=which is the minimum point because the parabola opens up.
F(1.25)= 2(1.25x1.25}-5(1.25)-3
= 3.125 -6.25 -3
= -6.125
The vetex are - {1.25, -6.125)
Axis of symmetry is whatever the value of x vetex and is (1.25)
x intercepts can be determined by making the equation equal to zero and solve for x.
2x^2-5x-3=0
we can determine x intercepts by factorizing.
(2x+1)(x-3)=0
x= -1/2= -0.5
and
x= 3
Therefore x intercepts are(-0.5, 3,)
Y intercepts can be determine by plugging 0 for x in the equation.
that is the value of y when x equals zero.
2x^2-5x-3
2(0)(0)-5(0}-3
y intercepts is = -3
For the parabola it's easy to draw too with all above information,but my computer is not capable of drawing graph at this time,but if i can find a way i will post the graph for you,i have ben trying to figure out away to draw graph for online tutoring of this kind.
But with all above information you will be alright.
Moruph Osuolale
mosuolal@uncc.edu
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