SOLUTION: I need help solving this quadratic equation: {{{25x^2-16=0}}}

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Question 223959: I need help solving this quadratic equation: 25x%5E2-16=0
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
25x%5E2-16=0
Can be rewritten as:
%285x%29%5E2-+4%5E2=0
Now, it is a "difference of squares" -- which is a special factor case:
%285x%2B4%29%285x-4%29=0
To solve, set each to zero -- which yields:
x = {-4/5 , 4/5}