Question 223927: How do I graph a line using the slope of m=1/3 and point (3,-1)?
Answer by drj(1380)   (Show Source):
You can put this solution on YOUR website! How do I graph a line using the slope of m=1/3 and point (3,-1)?
Step 1. The slope m is given as
Step 2. Let (x1,y1)=(3,-1) or x1=2 and y1=1 . Let other point be ((x2,y2)=(x,y) or x2=x and y2=y.
Step 3. Now we're given  . Substituting above values and variables in the slope equation m yields the following steps:
Step 4. Multiply x-3 to both sides to get rid of denominator on right side of equation.
Step 5. Now add -1 to both sides of equation to solve for y.
The slope m=1/3 and y-intercept is -2 at point (0,-2).
Now you have two points (0,-2) and (3,-1) to draw a line.
Note: the above equation can be rewritten as
 Note in this form: when y=0 then x=6 at point (6,0).
And the graph is shown below which is consistent with the above steps.
| Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc |
Equation  describes a sloping line. For any
equation ax+by+c = 0, slope is  .- X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 2/0.333333333333333 = 6.00000000000001.
- Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 2/-1 = -2.
- Slope is -0.333333333333333/-1 = 0.333333333333333.
- Equation in slope-intercept form: y=0.333333333333333*x+-2.
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I hope the above steps were helpful. Good luck in your studies!
Respectfully,
Dr J
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra.
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