SOLUTION: Professor says this one is easy but I don't see it? Please help me 1/n + 1/n+1= -1/n(n+1) I know that the LCD=n(n+1) and n can not equal zero. That is as far as I can get.

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Professor says this one is easy but I don't see it? Please help me 1/n + 1/n+1= -1/n(n+1) I know that the LCD=n(n+1) and n can not equal zero. That is as far as I can get.      Log On


   

Question 223593: Professor says this one is easy but I don't see it? Please help me
1/n + 1/n+1= -1/n(n+1)

I know that the LCD=n(n+1) and n can not equal zero. That is as far as I can get.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
1%2Fn+%2B+1%2F%28n%2B1%29 = -1%2F%28n%28n%2B1%29%29
:
Multiply by n(n+1)
:
n(n+1)*1%2Fn + n(n+1)*1%2F%28n%2B1%29 = n(n+1)*-1%2F%28n%28n%2B1%29%29
:
Cancel the denominators and you have:
(n+1) + n = -1
2n + 1 = -1
2n = -1 - 1
2n = -2
n = -1
;
But you can see that this value for n would make you have a denominator of 0,
so there is no solution