Question 223524: This is really hard for me :(
This Company manufactures three types of dweezle, type K, Type Z, and type F. Each type of dweezle is composed of two compounds, iron and zinc. Each pound of type K is 12 ounces of iron and 4 ounces of zinc while each pound of type Z is 12 ounces of zinc and 4 ounces of iron. Type F requires 8 ounces of each per pound.
Zinc is somewhat more difficult to work with, making type Z more costly to produce. A pound of type Z requires 9.6 man-hours to produce while a pound of type K requires only 6 man-hours and type F only 8.
The company has 125 pounds of zinc and 175 pounds of iron and only 2180 man-hours available for production, how many of type K and type Z can the Company make?
Goodness this is a pain, I tried and tried and keep getting different solutions. Please HELP!
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! This Company manufactures three types of dweezle, type K, Type Z, and type F. Each type of dweezle is composed of two compounds, iron and zinc.
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Each pound of type K is 12 ounces of iron and 4 ounces of zinc
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while each pound of type Z is 12 ounces of zinc and 4 ounces of iron.
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Type F requires 8 ounces of each per pound.
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Zinc is somewhat more difficult to work with, making type Z more costly to produce.
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A pound of type Z requires 9.6 man-hours to produce
while a pound of type K requires only 6 man-hours
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and type F only 8.
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The company has 125 pounds of zinc and 175 pounds of iron and only 2180 man-hours available for production,
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how many of type K and type Z can the Company make?
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This IS a pain, the guy that wrote this, ought to get back on his medication.
:
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Let k, z, f be the no. of each items made, respectively
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The zinc amt equation
4k + 12z + 8f = 125
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The iron amt equation
12k + 4z + 8f = 175
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The man-hour equation
6k + 9.6z + 8f = 2180
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I checked this using the matrix feature on my calc and there are not 3 positive
solutions to this. Something is not right here
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