SOLUTION: shawn begins walking to nathan's house at 3mph. Nathan leaves his house at the same time walking towards shawn's house at 2mph.. how long will it be before they meet if the dista

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Question 223386: shawn begins walking to nathan's house at 3mph. Nathan leaves his house at the same time walking towards shawn's house at 2mph.. how long will it be before they meet if the distance between the houses is 4 miles?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
D=RT
4=(3+2)T
4=5T
T=4/5
T=.8 HOURS IS THE WALKING TIME.