SOLUTION: Factor each polynomial completely. 3x3y2 - 3x2y2 - 3xy2 Each first number 3 is a regular number 3 the rest of the numbers are "to the power" numbers. I really need this one exp

Algebra ->  Customizable Word Problem Solvers  -> Unit conversion -> SOLUTION: Factor each polynomial completely. 3x3y2 - 3x2y2 - 3xy2 Each first number 3 is a regular number 3 the rest of the numbers are "to the power" numbers. I really need this one exp      Log On

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Question 223280: Factor each polynomial completely. 3x3y2 - 3x2y2 - 3xy2 Each first number 3 is a regular number 3 the rest of the numbers are "to the power" numbers. I really need this one explained to make sure I will get the rest of them right please and thank you!!!
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
common factors first ___ 3xy^2(x^2 - x - 1)

the polynomial is not factorable