SOLUTION: Can someone please help me understand how to solve this problem. Thank you in advance.
Area of a painting.
A rectangular painting with a width of X centimeters has an area of
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: Can someone please help me understand how to solve this problem. Thank you in advance.
Area of a painting.
A rectangular painting with a width of X centimeters has an area of
Log On
Question 222956: Can someone please help me understand how to solve this problem. Thank you in advance.
Area of a painting.
A rectangular painting with a width of X centimeters has an area of x^2 + 50x square centimeters. Find a binomial that represents the length. Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! A rectangular painting with a width of X centimeters has an area of x^2 + 50x square centimeters. Find a binomial that represents the length.
Area equals length * width.
you have the area equal to x^2 + 50x
If you let x = width, and y = length, then you get:
area = x*y = x^2 + 50x
divide both sides of this equation by x to get:
y = (x^2 + 50x) / y = x+50
your answer should be:
y = x+50
if that's true, then x * (x+50) = x*y = area of the painting.
