Question 222923: the length of a rectangle is 2 km less than 3 times the width. if the perimeter is 68 km, what is the length of the rectangle? Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! The length of a rectangle is 2 km less than 3 times the width. If the perimeter is 68 km, what is the length of the rectangle?
Step 1. Perimeter P means adding up all the lengths of the sides of a rectangle.
Step 2. Let w be the width.
Step 3. Let 3w-2 be the length.
Step 4. Then P=w+w+3w-2+3w-2=68 km.
Step 5. Solving the equation in Step 4 leads to the following steps:
Cartoon (animation) form: For tutors: simplify_cartoon( w+w+3w-2+3w-2=68 )
If you have a website, here's a link to this solution.
DETAILED EXPLANATION
Look at . Added fractions or integers together It becomes . Look at . Moved to the right of expression It becomes . Look at . Removed extra sign in front of It becomes . Look at . Eliminated similar terms,,, replacing them with It becomes . Look at . Added fractions or integers together It becomes . Look at . Remove unneeded parentheses around factor It becomes . Look at . Moved these terms to the left It becomes . Look at . Added fractions or integers together It becomes . Look at . Removed extra sign in front of It becomes . Look at . Solved linear equation equivalent to 8*w-72 =0 It becomes . Result: This is an equation! Solutions: w=9.
Universal Simplifier and Solver
Done!
With w=9, then 3w-2=27-2=25 and P=2(9+25)=68... which is a true statement.
Step 6. ANSWER: Length is 25 kilometers.
I hope the above steps were helpful.
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