SOLUTION: the sum of two numbers is 10. the sum of their squares is 52. find the numbers. i got so far" let x=one number let y=other number x+y=10 -y -y x=10-y THEN using substituti

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Question 22263: the sum of two numbers is 10. the sum of their squares is 52. find the numbers.
i got so far"
let x=one number
let y=other number
x+y=10
-y -y
x=10-y
THEN using substitution...
x²+y²=61
(10-y)²+y²=61
100-10y-10y+y²+y²=61
100-20y+2y²=61
2y²-20y+39=0
Now use the quadratic formula or factor it...
Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
x+y=10
y=-x+10
x%5E2%2By%5E2=52
x%5E2%2B%28-x%2B10%29+=+52
x%5E2-x%2B10=52
x%5E2-x-42
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a=1, b=-1, c=-42
x+=+%28-%28-1%29+%2B-+sqrt%28+%28-1%29%5E2-4%281%29%28-42%29+%29%29%2F2%2A1%29+
x+=+%281+%2B-+sqrt%281%2B168%29%29%2F2%29+
simplify: add x=7
10-7 =3
Hence, the two numbers are 3, and 7.