SOLUTION: Train A and B are traviling the same direction on parallel tracks. Train A is traviling at 100 miles per hour and train B is traviling at 120 miles per hour. Train A passes a stati
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Question 222124: Train A and B are traviling the same direction on parallel tracks. Train A is traviling at 100 miles per hour and train B is traviling at 120 miles per hour. Train A passes a station at 5:25 p.m. If train B passes the same station at 5:40 p.m., at what time will train B catch up with train A? Found 2 solutions by checkley77, ankor@dixie-net.com:Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! 100T=120(T-.25)
100T=120T-30
100T-120T=-30
-20T=30
T=-30/-20
T=1.5 HOURS AFTER TRAIN A LEAVES THE STATION B TRAIN WILL CATCH UP.
5:25+1:30=6:55 IS THE CATCH-UP HOUR.
You can put this solution on YOUR website! Train A and B are traveling the same direction on parallel tracks.
Train A is traveling at 100 miles per hour and train B is traveling at 120 miles per hour.
Train A passes a station at 5:25 p.m.
If train B passes the same station at 5:40 p.m., at what time will train B catch up with train A?
:
from the given information, we know that train B is 15 min (.25 hr) behind
train A, when train A passes the station
:
The distance between the trains at this time: .25 * 120 = 30 mi
:
Let t = time required for train B to catch train a
:
write a distance equation: Dist = speed * time
:
Train b travel dist = Train a travel dist + 30 mi
120t = 100t + 30
120t - 100t = 30
20t = 30
t =
t = 1.5 hr or 1 hr 30 min
:
5:25 + 1:30 = 6:55 pm, B catches A
:
:
Check solution by finding the distances (train b travels 30 mi more than train b)
120 * 1.5 = 180 mi
100 * 1.5 = 150 mi
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difference = 30 mi
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