You can put this solution on YOUR website! How many grams of pure silver must a silversmith mix with a 45% silver alloy to produce 200 grams of a 50% alloy?
:
Let x = amt of pure silver required to do this
Then
(200-x) = amt of 45% silver alloy required
;
x + .45(200-x) = .50(200)
:
x + 90 - .45x = 100
x - .45x = 100 - 90
.55x = 10
x =
x = 18.2 grams of pure silver
:
:
Check solution: 200-18.2 = 181.8 grams of 45% silver
18.2 + .45(181.8) = .5(200)
18.2 + 81.8 = 100
100 = 100