SOLUTION: Hi, I have an absolute value problem. I tried solving it like a regular equation, but when I check it it is wrong. The problem is 6|5x+45|-113=7.
Thanks in advance.
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-> SOLUTION: Hi, I have an absolute value problem. I tried solving it like a regular equation, but when I check it it is wrong. The problem is 6|5x+45|-113=7.
Thanks in advance.
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Question 221656: Hi, I have an absolute value problem. I tried solving it like a regular equation, but when I check it it is wrong. The problem is 6|5x+45|-113=7.
Thanks in advance. Found 3 solutions by stanbon, sofiyac, drj:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 6|5x+45|-113=7
6|5x+45| = 120
|5x+45| = 20
5x+45 = 20 or 5x+45 = -20
5x = -25 or 5x = -65
x = -5 or x = -13
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Cheers,
Stan H.
You can put this solution on YOUR website! ok, so when you have an absolute value problem you have to consider two cases (one regular one and the other one with the negative in front of the absolute value parenthesis)
CASE 1 divide both sides by 30
CASE 2
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You can put this solution on YOUR website! Hi, I have an absolute value problem. I tried solving it like a regular equation, but when I check it it is wrong. The problem is 6|5x+45|-113=7.
Thanks in advance.
Step 1. Note that is the same as 5x+45 when 5x+45 is positive and -(5x+45) when 5x+45 is negative.
Step 2. Let
Add 113 to both sides
Divide 6 to both sides of the equation
and or
and
and
Step 3. ANSWER is x=-5 and x=-13.
I hope the above steps were helpful.
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
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