Question 221523: Determine whether there are two consecutive odd integers such that 5 times the first exceeds 3 times the second by 54. Found 2 solutions by stanbon, drj:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Determine whether there are two consecutive odd integers such that 5 times the first exceeds 3 times the second by 54.
--------------
1st odd: 2x-1
2nd odd: 2x+1
---------------------
Equations:
5(2x-1) = 3(2x+1)
10x-5 = 6x+3
4x = 8
x = 2
-------
1st odd: 2*2-1 = 3
2nd odd: 2*2+1 = 5
==========================
Cheers,
Stan H.
You can put this solution on YOUR website! Determine whether there are two consecutive odd integers such that 5 times the first exceeds 3 times the second by 54.
Step 1. Let n be the first odd integer.
Step 2. Let n+2 be then next consecutive odd integer.
Step 3. Let 5n be 5 times the first odd integer.
Step 4. Let 3(n+2) be 3 times the second odd integer.
Step 5. Then, 5n=3(n+2)+54 since 5 times the first exceeds 3 times the second by 54
Step 6. Solving the equation in Step 5 yields the following steps:
Subtract 3n from both sides of the equation
Divide by 2 to both sides of the equation yields
but n is an even integer.
Step 8. ANSWER: Therefore there are no odd integers that satisfies the given problem statement.
I hope the above steps were helpful.
For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.