Question 221482:  Give exact and approximate solutions to three decimal places. 
y^2-4y+4=9
 
Thank you! 
 Found 2 solutions by  jim_thompson5910, RAY100: Answer by jim_thompson5910(35256)      (Show Source):  Answer by RAY100(1637)      (Show Source): 
You can  put this solution on YOUR website! y^2 -4y +4 = 9 
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y^2 -4y -5 =0,,,,,,,,,,factor 
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(y-5)(y+1) =0 
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y= 5,,,-1 
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check,,,,(5),,,5^2 -4*5 +4 = 9,,,,,25-20 +4 =9,,,,ok 
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(-1),,,,(-1)^2 -4(-1) +4 = 1+4+4 =9,,,,,,ok 
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If  we  use  thew  quadratic  formula 
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a= 1,,,,b=-4,,,,c=-5 
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x=[ -(-4) +/- sqrt{ (-4)^2 -4(1)(-5)}] / 2(1) 
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x=[4 +/- sqrt{ 16+20}]/2 
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x=[ 4+/- sqrt36] /2 
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x= [4 +/- 6] /2 
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x= 10/2=5,,,,,,-2/2=-1 
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