SOLUTION: The perimeter of a rectangular playground area is 308 feet. If the length of the playground is 34 feet more than twice the width, find the length and width of the playground

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Question 221184: The perimeter of a rectangular playground area is 308 feet. If the length of the playground is 34 feet more than twice the width, find the length and width of the playground
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangular playground area is 308 feet. If the length of the playground is 34 feet more than twice the width, find the length and width of the playground.

Step 1. Perimeter P means adding all 4 sides of a rectangle.

Step 2. Let w be the width and 2w be twice the width

Step 3. Let 2w+34 since the length is 34 feet more than twice the width.

Step 4. Then P=w+w+2w+34+2w+34=308 feet as given by the problem. Simplifying yields, 6w+68=308.

Subtract 68 from both sides of the equation

6w%2B68-68=308-68

6w=240

Divide 6 to both sides of the equation

6w%2F6=240%2F6}

w=40 and 2w+34=80+34=114}}}

P=40%2B40%2B114%2B114=308 which is a true statement.

Step 5. ANSWER: The dimensions of the playground is 40 and 114 feet.

I hope the above steps and explanation were helpful.

For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry please visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Also, good luck in your studies and contact me at john@e-liteworks.com for your future math needs.

Respectfully,
Dr J