SOLUTION: Solve for x:
2x+1 <3
_____
x-5
I tried this:
x and x cancel eachother so its
x+1 <3
___
-5
then multiply the demonator and numerator by 5/1 so that leaves
Algebra ->
Expressions-with-variables
-> SOLUTION: Solve for x:
2x+1 <3
_____
x-5
I tried this:
x and x cancel eachother so its
x+1 <3
___
-5
then multiply the demonator and numerator by 5/1 so that leaves
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Question 220734: Solve for x:
2x+1 <3
_____
x-5
I tried this:
x and x cancel eachother so its
x+1 <3
___
-5
then multiply the demonator and numerator by 5/1 so that leaves x<3??? Found 2 solutions by tutor_paul, stanbon:Answer by tutor_paul(519) (Show Source):
You can put this solution on YOUR website!
Whoa there... you can't cancel the x's in this case...you can only cancel factors, not when x is added to something.
In this case, first multipy each side of the inequality by (x-5):
Now you can cancel the x-5 terms on the left because they are factors. This leaves you with:
Now multipy out the term on the right:
Next you want to get the x terms on one side of the inequality and other terms on the other side.
Add -3x to both sides:
Simplify:
Add -1 to each side:
Simplify:
Multiply each side by -1. Note, when you multiply each side by a negative number, you must swap the inequality:
==============
Good Luck,
tutor_paul@yahoo.com
You can put this solution on YOUR website! Solve for x:
2x+1 <3
_____
x-5
======================
(2x+1)/(x-5) < 3
---------
You can see that x cannot be 5
----------------
Draw a Number line and mark x = 5
-------------------
Now check a value from each of the resulting intervals
in the inequality to see where the solution set lies.
----------------------
Check x = 0; you get: (1/1)<3 ; true, so solutions in (-inf,5)
----------------------
Checx x = 10; you get: 21/5 < 3 ; false so no solutions in (5,+inf)
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Let's see what it looks like:
I'll graph the left side and the right side separately:
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Cheers,
Stan H.
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