SOLUTION: For what values of x does the graph of f(x) = 2x^3 - 3x^2 - 6x + 51 have a horizontal tangent? smaller and larger values?

Algebra ->  Graphs -> SOLUTION: For what values of x does the graph of f(x) = 2x^3 - 3x^2 - 6x + 51 have a horizontal tangent? smaller and larger values?       Log On


   



Question 220705: For what values of x does the graph of f(x) = 2x^3 - 3x^2 - 6x + 51 have a horizontal tangent?
smaller and larger values?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
For what values of x does the graph of f(x) = 2x^3 - 3x^2 - 6x + 51 have a horizontal tangent?
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Take the derivative; set it to zero; solve for "x".
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f'(x) = 6x^2-6x-6 = 0
x^2-x-1 = 0
x = [1 +- sqrt(1-4*1*-1)]/2
x = [1 +- sqrt(5)]/2
x = (1+(sqrt(5))/2 or (1-(sqrt(5))/2
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Let's see what it looks like:
graph%28400%2C300%2C-10%2C10%2C-60%2C60%2C2x%5E3-3x%5E2-6x%2B51%29
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Cheers,
Stan H.