Question 220559: Could you please explain to me how to combine the terms of the expression into only one logarithm.
log3(x)+log3(x+2)-log2(3x-4)^2 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Could you please explain to me how to combine the terms of the expression into only one logarithm.
log3(x)+log3(x+2)-log2(3x-4)^2
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Solve 3^y = 2
y = ln2/ln3 = 0.6309
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log3[x(x+2)] - 0.6309log3[(3x-4)^2]
log3[x(x+2)] - log3(3x-4)^(2(0.6309))
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log3[x(x+2)/(3x-4)^1.2619]
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Cheers,
Stan H.
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