Question 220517: Can someone please help me?
Solve for x in terms of k
log{subscript 5}x + log{subscript 5)(x+2) = k
x= ?
Find x if k=8 ? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Solve for x in terms of k
log{subscript 5}x + log{subscript 5)(x+2) = k
x= ?
Find x if k=8 ?
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log5(x) + log5(x+2) = k
Rewrite:
log4[x(x+2)] k
x^2+2x = 4^k
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Now, if k = 8 you get:
x^2 + 2x = 4^8
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x^2+2x- 65536 = 0
Comment:
This does not factor neatly.
It can be solved using the quadratic formula.
I'll leave that to you.
Cheers,
Stan H.
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