SOLUTION: Jade and Rocky are 36 miles apart and start simultaneously biking toward each other. Jade is going 2mph faster than Rocky, who is biking at 8mph. How far will Jade have biked at

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Question 220104: Jade and Rocky are 36 miles apart and start simultaneously biking toward each other. Jade is going 2mph faster than Rocky, who is biking at 8mph. How far will Jade have biked at the time she meets up with Rocky?
Found 2 solutions by colliefan, MathTherapy:
Answer by colliefan(242) About Me  (Show Source):
You can put this solution on YOUR website!
Jade and Rocky are 36 miles apart and start simultaneously biking toward each other. Jade is going 2mph faster than Rocky, who is biking at 8mph. How far will Jade have biked at the time she meets up with Rocky?


If Rocky is biking 8 mph, Jade must be going 10 mph.
That means in one hour, Jade will have traveled 10 miles and Rocky 8 miles and so they will have covered 18 miles between them. This is half of the total distance so it must take 2 hours for them to cover the whole distance. Checking that, in 2 hrs Jade will have gone 20 miles and Rocky 16 mi. They would have covered the whole distance in 2 hours and Jade would have biked 20 miles.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Let Jade’s distance to the meeting point be J, then Rocky’s distance = 36 – J

D = ST, or T+=+D%2FS

Jade’s time to get to meeting point = J%2F10, while Rocky’s is: %2836-J%29%2F8. Both times are equal, and therefore we have: J%2F10+=+%2836-J%29%2F8.

8J = 10(36 – J) -------- Cross-multiplying

8J = 360 – 10J ------- 18J = 360

Therefore, Jade’s distance to meeting point, or J = 360%2F18, or highlight_green%2820%29 miles

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