SOLUTION: what is the y-intercept of f(x)={x^2-4x-5} over {x^2+2x+1}? and how did you get that?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: what is the y-intercept of f(x)={x^2-4x-5} over {x^2+2x+1}? and how did you get that?      Log On


   

Question 220083: what is the y-intercept of f(x)={x^2-4x-5} over {x^2+2x+1}? and how did you get that?
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
The y-intercept is where a graph crosses (or intersects) the y-axis. Think about the points on the y-axis. Think about the coordinates of points on the y-axis. After some thought I hope it is obvious the all the points on the y-axis have an x-coordinate of 0. So to find the y-intercept of a function, use a value of 0 for x. IOW, f(0) is the y-intercept.

f%28x%29+=+%28x%5E2-4x-5%29%2F%28x%5E2%2B2x%2B1%29

So the y-intercept is (0, -5).