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Question 219999: please help.
The line 2x+5y=10 passes through the points (3c+1,d-5) and (c+4,2d+6). Find the values for c and d
Answer by chibisan(131)   (Show Source):
You can put this solution on YOUR website! subt (3c+1,d+5) first to make a new equation
2(3c+1)+5(d+5) = 10
6c+2+5d+5-10=0
6c+5d=3 --(Eqn1)
Subt (c+4,2d+6) to make another equation
2(c+4)+5(2d+6)=10
2c+8+10d+30=10
2c+10d+38-10=0
2c+10d=-28 --(Eqn2)
Solve it simultaneously
6c+5d=3 --(Eqn1)
2c+10d=-28 --(Eqn2)
(eqn1)x2
12c+10d=6 --(eqn 3)
(eqn3) - (eqn2)
(12c+10d)-(2c+10d)=6-(-28)
10c=34
c=3.4
subt c=3.4 to eqn 2
2(3.4)+10d= -28
10d=-28-6.8
10d= -34.8
d= -3.48
c=3.4 , d= -3.48 (ans)
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