Question 219584: X^2 - 3X
i am suppose to determin the constant that should be added to the binomial so that it becomes a perfect square trinomial.
Found 2 solutions by Alan3354, RAY100:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Do it like this one.
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If the coefficient a of the x^2 term = 1, then add
(b/2)^2.
b = 12
(b/2)^2 = 36
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x^2 + 12x + 36 = (x+6)^2
Answer by RAY100(1637)  (Show Source):
You can put this solution on YOUR website! if we review,,,(a+b)^2 = (a+b) * (a+b) = a^2 +2ab +b^2
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looking at coefficients, 2given / 2(half) =1,,,1^2 = 1(3rd coefficient)
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therefore if we have 2nd coefficient, take half and square it to get 3rd coefficient.
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x^2 -3x + 2.25,,,,,,,-3/2=-1.5,,,,,-1.5^2 = 2.25
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check,,,,(x-1.5)^2 = (x-1.5)(x-1.5) = x^2 -1.5x -1.5x +2.25 = x^2 -3x +2.25
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note,,,1.5 = 3/2
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