SOLUTION: A car radiator contains 10 liters of 20% anitfreeze solution. How many liters of pure antifreeze are needed to make the solution 50% antifreeze without replacement?
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Question 219499: A car radiator contains 10 liters of 20% anitfreeze solution. How many liters of pure antifreeze are needed to make the solution 50% antifreeze without replacement? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! This assumes that the radiator will hold whatever added
antifreeze you try to put in.
In words:
(final liters of antifreeze)/(final liters of total mixture) = 50%
Let = liters of antifreeze to be added
Multiply both sides by
6 liters of antifreeze needs to be added to make mixture 50%
check answer:
OK
