SOLUTION: The perimeter of the triangle is 48centimeters. The longest side is 6 centimeters less than the sum of the other two sides. Twice the shortest side is 5 centimeters less than the l
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Question 219497: The perimeter of the triangle is 48centimeters. The longest side is 6 centimeters less than the sum of the other two sides. Twice the shortest side is 5 centimeters less than the longest side. Find the lengths of each side.
I began by trying to come up with the equations: (a=shortest side; b=middle, c=longest side; and P=48)
a+b+c=48
2a=5-c
c=6-(a+b)
You can put this solution on YOUR website! a+b+c=48
c=a+b-6
2a=c-5
a+b+(a+b-6)=48
2a+2b-6=48
2a=2b=48+6
2a+2b=54
a+b=27
27+c=48
c=48-27
c=21 ans. for the longest side.
2a=21-5
2a=16
2a=16/2
a=8 ans.
8+b=27
b=27-8
b=19 ans.
Proof:
8+19+21=48
48=48
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