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Question 219470: 1.Find an equation of a line that passes through the points (-2,-3) and (-1,1).
y=m(x-x1)+y1
y=4(x-(-2) + (-3)
y=4x +8 -3
y=4x + 5 (answer) Is this correct?
2. Find the equation of the line that contains the point (0,3) and is perpendicular to the line y=1/2X -1. My answer: y=-2x+1 Is this correct?
3. Find x intercept and y-intercept for the line with the equation y=4x + 1/2 and sketch the graph.
Y= 1/2
x= -2 Is this correct.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! 1.Find an equation of a line that passes through the points (-2,-3) and (-1,1).
y=m(x-x1)+y1
y=4(x-(-2) + (-3)
y=4x +8 -3
y=4x + 5 (answer) Is this correct?
If you sub for x and y, both points satisfy the eqn, so it's correct.
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2. Find the equation of the line that contains the point (0,3) and is perpendicular to the line y=1/2X -1.
My answer: y=-2x+1 Is this correct?
The point (0,3) isn't on the line, so it's not correct.
The slope, m, is -2
y-3 = -2x
y = -2x + 3
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3. Find x intercept and y-intercept for the line with the equation y=4x + 1/2 and sketch the graph.
Y= 1/2
is the y-intercept
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x= -2 Is this correct.
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x-intercept:
y = 0
0 = 4x + 1/2
x = -1/8
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