SOLUTION: In a shipment of 40 televisions, 3 are defective. If 2 sets are randomly selected and tested, what is the probability that both are defective? (The first one is not replaced before
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Question 218971: In a shipment of 40 televisions, 3 are defective. If 2 sets are randomly selected and tested, what is the probability that both are defective? (The first one is not replaced before the second one is selected.) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! In a shipment of 40 televisions, 3 are defective. If 2 sets are randomly selected and tested, what is the probability that both are defective? (The first one is not replaced before the second one is selected.)
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P(defective) = 3/40
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P(both defective) = (3/40)(2/39)
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Cheers,
Stan H.
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