SOLUTION: A worker at a particular company is in charge of a tank that holds and dispenses a certain liquid chemical throughout the factory. The tank has two pipes dispensing liquid from the

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Question 218913: A worker at a particular company is in charge of a tank that holds and dispenses a certain liquid chemical throughout the factory. The tank has two pipes dispensing liquid from the tank to the factory. One of the pipes can empty the tank when full in 3 hours. The other pipe can empty the tank when full in 4 hours. A third pipe is used to fill the tank with the liquid chemical and it can fill the tank in 45 mins. If the Tank was half full and all three pipes were running at full capacity, then how long would it take for the tank to be completely full?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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A worker at a particular company is in charge of a tank that holds and dispenses
a certain liquid chemical throughout the factory.
The tank has two pipes dispensing liquid from the tank to the factory.
One of the pipes can empty the tank when full in 3 hours.
The other pipe can empty the tank when full in 4 hours.
A third pipe is used to fill the tank with the liquid chemical and it can fill the tank in 45 mins.
If the Tank was half full and all three pipes were running at full capacity,
then how long would it take for the tank to be completely full?
:
Let t = time required with all three pipes running
:
Let the full tank = 1. 1%2F2 = half a tank
:
45 min = .75 hrs
:
t%2F3 + t%2F4 + t%2F.75 = 1%2F2
Multiply equation by 12:
4t + 3t + 16t = 6
23t = 6
t = 6%2F23
which is:
6%2F23 * 60 = 15.65 minutes
:
:
Check solution using decimal for 6/23
.26%2F3 + .26%2F4 + .26%2F.75 = 1%2F2
.087 + .065 + .347 = .499 ~ .5