SOLUTION: let f(x)=3-x and g(x)=x^2-1 h(x)=(g(x))f(x)
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Question 21874
:
let f(x)=3-x and g(x)=x^2-1
h(x)=(g(x))f(x)
Answer by
algebrapro18(249)
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well you are multiplying the two functions so just multiply
h(x)=(3-x)(x^2-1)
h(x)=3x^2-3-x^3+x
h(x)=-x^3+3x^2+x-3