Question 218499: The sum of three times the least of three consecutive integers and the greatest is 46. What are the three integers Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! The sum of three times the least of three consecutive integers and the greatest is 46. What are the three integers?
Step 1. Let n be an integer and 3n be three times the least of 3 consecutive integers
Step 2. Let n+1 and n+2 be the next two consecutive integer.
Step 3. Let 3n+n+2=46 since the sum of three times the least of three consecutive integers and the greatest is 46.
Step 4. Solving yields the following steps:
Subtract 2 from both sides of the equation
Divide 4 to both sides of the equation
Check 2n+n+2=46...3*11+13=46...which is a true statement.
Step 5. The integers are 11, 12, and 13.
I hope the above steps were helpful.
For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
