SOLUTION: I'm at the review section of my Trig book and to be honest, I don't remember what to do here. I think one has to square the root away and square the other side, and subtract the 44

Algebra ->  Trigonometry-basics -> SOLUTION: I'm at the review section of my Trig book and to be honest, I don't remember what to do here. I think one has to square the root away and square the other side, and subtract the 44      Log On


   

Question 218411: I'm at the review section of my Trig book and to be honest, I don't remember what to do here. I think one has to square the root away and square the other side, and subtract the 44, but then I'm not sure. I'd rather not have x^2-44 over 7 equals x, but could that be right?
+sqrt%28+7x+%2B+44+%29+ = x
Found 2 solutions by josmiceli, Alan3354:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+sqrt%28+7x+%2B+44+%29+=+x
Square both sides
7x+%2B+44+=+x%5E2
x%5E2+-+7x+-+44+=+0
I can solve with quadratic formual
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a+=+1
b+=+-7
c+=+-44
x+=+%28-%28-7%29+%2B-+sqrt%28+%28-7%29%5E2-4%2A1%2A%28-44%29+%29%29%2F%282%2A1%29+
x+=+%287+%2B-+sqrt%2849+%2B+176%29%29%2F2+
x+=+%287+%2B-+sqrt%28225%29%29%2F2+
x+=+%287+%2B-+15%29%2F2+
x+=+11
x+=+-4
check answers:
+sqrt%28+7x+%2B+44+%29+=+x
+sqrt%28+7%2A11+%2B+44+%29+=+11
+sqrt%28+121+%29+=+11
11+=+11
and
+sqrt%28+7%2A%28-4%29+%2B+44+%29+=+-4
+sqrt%28+16+%29+=+-4
+-4+=+-4 (one of the square roots is minus)
OK

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
+sqrt%28+7x+%2B+44+%29+ = x
Square both sides
7x + 44 = x^2
x^2 - 7x - 44 = 0
(x-11)*(x+4) = 0
x = 11
x = -4