SOLUTION: what are 2 consecutive 2-digit numbers whose product is 812?
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Question 218403
:
what are 2 consecutive 2-digit numbers whose product is 812?
Found 2 solutions by
Fombitz, rfer
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Answer by
Fombitz(32388)
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N*(N+1)=812
N^2+N-812=0
(N-28)(N+29)=0
Two solutions
N-28=0
N=28, then the two numbers are 28 and 29.
N+29=0
N=-29. then the two numbers are -29 and -28.
Answer by
rfer(16322)
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28*29=812
sq rt of 812=28.495
then take the whole number above and below