Question 218316: Two row boats are traveling at a steady speed of 10 miles/hr straight toward each other. At the moment when they are 40 miles apart, a messenger pigion takes off from one of the boats and flies at a steady speed of 25 miles/hr directly to the other boat. It touches the second boat, turns around instantly, and returns at the same steady speed to the first boat. When it touches the first boat, it instantly turns around again and heads directly back to the second boat. The pegion repeats this back and forth flight pattern over and over again at the same speed until the boats meet. From the moment the pigion took off from the firts boat until the final meting of the boats, how much was the pegions total mileage? Justify your answer.
Found 2 solutions by ankor@dixie-net.com, solver91311:
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Two row boats are traveling at a steady speed of 10 miles/hr straight toward each other. At the moment when they are 40 miles apart, a messenger pigion takes off from one of the boats and flies at a steady speed of 25 miles/hr directly to the other boat. It touches the second boat, turns around instantly, and returns at the same steady speed to the first boat. When it touches the first boat, it instantly turns around again and heads directly back to the second boat. The pegion repeats this back and forth flight pattern over and over again at the same speed until the boats meet. From the moment the pigion took off from the firts boat until the final meting of the boats, how much was the pegions total mileage?
:
using the relative speed of the two boats (which is 20 mph), how long to travel 40 mi?
t = 40/20
t = 2 hrs
:
How far can the bird fly in 2 hrs at 25 mph
2 * 25 = 50 miles
Answer by solver91311(24713)  (Show Source):
You can put this solution on YOUR website!
Since each boat is traveling at a 10 mph steady state, the boats are closing with each other at a rate of 20 mph. That means that the distance between them will be reduced to zero in 2 hours. (40 miles divided by 20 mph is 2 hours). Now I don't know what a pegion or a pigion is, but presuming you actually meant pigeon, the bird would be flying at a steady state of 25 mph for 2 hours, or 50 miles would be the theoretical distance traveled. Of course that presumes the completely ludicrous idea that a bird of any kind can actually be traveling 25 miles per hour in one direction and then instantaneously reverse its direction and begin flying 25 miles per hour in the opposite direction. In practical terms, the distance traveled by the bird would be much less because of the time it would actually take for the animal to slow down, stop, turn around, and reacquire speed again.
John
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