SOLUTION: A student needs to put a 60% antifreeze solution in his car. If his car holds 10 quarts of antifreeze and he only has jugs of a 30% and 80% solution, how much of each solution shou

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Question 218140: A student needs to put a 60% antifreeze solution in his car. If his car holds 10 quarts of antifreeze and he only has jugs of a 30% and 80% solution, how much of each solution should be used to fill his car?
Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = amt of 30%
.
Let y = amt of 80%
.
x+y = 10,,,,,,,x=10-y
.
30% *x + 80% *y = 60% *10
.
.3x +.8y = 6,,,,,,,,,subst
.
.3(10-y) +.8y =6
.
3 -.3y +.8y =6
.
.5y = 3
,
y= 6 quarts,,,,,,,,x= 4 quarts
.
.check
.
.3(4) +.8(6) = .6(10)
.
1.2 +4.8 = 6,,,,,,ok
.