SOLUTION: How do you solve this problem: (x^2+7x)/3 = -4

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Question 21800: How do you solve this problem:
(x^2+7x)/3 = -4
Answer by algebrapro18(249) About Me  (Show Source):
You can put this solution on YOUR website!
well first clear the fraction

(x^2+7x)/3 = -4
3((x^2+7x)/3 = -4)
x^2+4x=-12

now simplify and solve using the quadratic formula but you will find there is no solution

x^2+4x+12=0

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

where a = 1, b = 4, & c = 12

x+=+%28-4+%2B-+sqrt%28+4%5E2-4%2A1%2A12+%29%29%2F%282%2A1%29+
x+=+%28-4+%2B-+sqrt%2816-4%2A12%29%29%2F%282%2A1%29
x+=+%28-4+%2B-+sqrt%2816-48%29%29%2F%282%29
x+=+%28-4+%2B-+sqrt%28-32%29%29%2F%282%29

since you can't take the square root of a negative number and get a real number back there are no real solutions.