SOLUTION: f(h(x))= when f(x) = 2x-1 and h = x+4 I took (2x-1)(x+4) and that gave me 2x^+8x-x-4 which i 2x^+7x-4 but my options for an answer are 2x+3, 2x+7, 7, and 2x^+7x-8 - i dont get a

Algebra ->  Rational-functions -> SOLUTION: f(h(x))= when f(x) = 2x-1 and h = x+4 I took (2x-1)(x+4) and that gave me 2x^+8x-x-4 which i 2x^+7x-4 but my options for an answer are 2x+3, 2x+7, 7, and 2x^+7x-8 - i dont get a      Log On


   

Question 217952: f(h(x))= when f(x) = 2x-1 and h = x+4
I took (2x-1)(x+4) and that gave me 2x^+8x-x-4 which i 2x^+7x-4 but my options for an answer are 2x+3, 2x+7, 7, and 2x^+7x-8 - i dont get any of them and i have been working on this for 2 hours. Can anyone please help me - thank you.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the notation is the thing

f(h(x)) means put h(x) in place of x in the function f(x)

f(h(x)) = 2(h(x)) - 1 = 2(x + 4) - 1 = 2x + 7