SOLUTION: Solve. 2(x-3)=5x+9 |2x+9| <3

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Question 21795: Solve.
2(x-3)=5x+9

|2x+9| <3
Found 2 solutions by queenofit, AnlytcPhil:
Answer by queenofit(120) (Show Source):
You can put this solution on YOUR website!
2(x-3)=5x+9
2x-6=5x+9
2x-5x=6+9
-3x=15
x=-5
On the absolute value question remember there are two answers. The absolute value can be either neg or pos. so set up two equations
2x+ 9 < 3 and -2x- 9 < 3
2x< -9 +3 -2x < 9 + 3
2X<-6 -2X < 12
X<-3 X>-6 remember to flip your sign
when you divide by a neg.
so you will have -3>x<-6

Answer by AnlytcPhil(1807) (Show Source):
You can put this solution on YOUR website!

Solve. 2(x-3)=5x+9 Use distributive property to remove parentheses: 2x - 6 = 5x + 9 Add +6 to both sides 2x - 6 = 5x + 9 + 6 + 6 ----------------- 2x = 5x + 15 Add -5x to both sides: 2x = 5x + 15 -5x -5x ----------------- -3x = 15 Divide both sides by -3 -3x/-3 = 15/-3 x = -5 ------------------------- |2x+9| < 3 Learn the two rules: If B is a positive number, then 1. |A| < B can be written " -B < A < +B ". 2. |A| > B can be writter " A < -B OR A > +B ". |2x+9| < 3 can be written -3 < 2x+9 < 3 Add -9 to all three "sides" -3 < 2x+9 < 3 -9 -9 -9 --------------- -12 < 2x < -6 Divide all three sides by 2 -6 < x < -3
Edwin
AnlytcPhil@aol.com