SOLUTION: Find the slope if it exists of the line containing the pair of points: (4,5) and (8,-3)

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Question 217928: Find the slope if it exists of the line containing the pair of points:
(4,5) and (8,-3)

Found 3 solutions by rfer, RAY100, drj:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
y=mx+b
y=-2x+13
slope=-2

Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
slope =m = (y2-y2)/(x2-x1)
.
for (4,5) and (8,-3)
.
m= (5-(-3))/(4-8) = 8/-4= -2,,,,,answer
.
if we reversed the coordinates, the answer remains the same,,,
.
m=(-3-5)/(8-4) = -8/4 = -2
.
Note, it is very easy to make a rough sketch, showing the points, and the rt triangle showing ,,,,delta x, and delta y.
.
Just remember,,slope is rise/run,,,or delta y/ delta x
.
positive slope rises to rt,,negative drops to right,,,
.

Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
Find the slope if it exists of the line containing the pair of points:
(4,5) and (8,-3)

However, here are the steps showing you how you can check your work with one of the points.

Step 1. The slope of the line m is given as

+m=%28y2-y1%29%2F%28x2-x1%29

where for our example is x1=4, y1=5, x2=8 and y2=-3 (think of slope=rise%2Frun). You can choose the points the other way around but be consistent with the x and y coordinates. You will get the same result.

Step 2. Substituting the above values in the slope equation gives

m=%28-3-5%29%2F%288-4%29

m=-8%2F4

m=-2

Step 3. The slope is calculated as -2 or m=-2

Step 4. Now use the slope equation of step 1 and choose one of the given points. I'll choose point (4,5). Letting y=y2 and x=x2 and substituting m=-2 in the slope equation given as,

+m=%28y2-y1%29%2F%28x2-x1%29


+-2=%28y-5%29%2F%28x-4%29

+-2=%28y-5%29%2F%28x-4%29

Step 5. Multiply both sides of equation by x-4 to get rid of denomination found on the right side of the equation


+-2%28x-4%29=%28x-4%29%28y-5%29%2F%28x-4%29


+-2%28x-4%29=y-5


Step 6. Now simplify and put the above equation into slope-intercept form.

-2x%2B8=y-5

Add 5 to both sides of the equation

-2x%2B8%2B5=y-5%2B5

-2x%2B13=y

y=-2x%2B13 ANSWER in slope-intercept form. m=-2 and y-intercept=13

Step 7. See if the other point (8,-3) or x=8 and y=-3 satisfies this equation

y=-2x%2B13

-3=-2%2A8%2B13 which is a true statement

-3=-3 So the point (8,-3) satisfies the equation and is on the line. In other words, you can use the other point to check your work.

Note; above equation can be also be transform into standard form as

2x%2By=13

See graph below to check the above steps and note the slope and the y-intercept at x=0

graph%28400%2C400%2C+-5%2C15%2C-5%2C15%2C+-2x%2B13%29

I hope the above steps were helpful.

And good luck in your studies!

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Respectfully,
Dr J