Question 217921: simplify i^29
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! i = sqrt (-1) =i
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i^2 = (-1)
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i^3 = -i
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i^4 = +1
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and then they repeat,,,every 4
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i^5 = sqrt(-1)
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etc
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Since it the pattern does repeat for every 4th power,,
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to find any power,,,divide by 4,,,and the REMAINDER is the power of concern,
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for example,,i^5 =(5/4 = 1 R1)= i^1 =i= sqrt(-1)
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for this problem,,,i^29 = (29/4 =7R1)=i^1 =i =sqrt(-1)
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