SOLUTION: find the vertex and the axis of symmetry of the parabola y=6x2+11x

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Question 217858: find the vertex and the axis of symmetry of the parabola
y=6x2+11x
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
y=6x^2+11x
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+6x%5E2+%2B11x%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, 6x^2 +11x).
Symmetry (x)=-b/2a=-11/2*6=-11/12 ans.
When x=-11/12 then:
y=6(-11/12)^2+11(-11/12)
y=6*.8403-121/12
y=5.042-10.083
y=-5.041
The vertex is (-11/12,-5.041)