Question 217651: the squares of 2 consecutive odd numbers differ by 88, what are the numbers?
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! Let x,,,,x+2 ,,,,be consecutive odd numbers
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(x+2)^2 -(x)^2 =88
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x^2 +4x +4 -x^2 =88
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4x =84
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x=21
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Numbers are 21,,23
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check
23^2-21^2 = 88,,,,,,ok
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