SOLUTION: What is the equation of a line with the slope of 13/16, passing through points (18,13)?

Algebra ->  Linear-equations -> SOLUTION: What is the equation of a line with the slope of 13/16, passing through points (18,13)?      Log On


   

Question 217648: What is the equation of a line with the slope of 13/16, passing through points (18,13)?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

If you want to find the equation of line with a given a slope of 13%2F16 which goes through the point (18,13), you can simply use the point-slope formula to find the equation:


---Point-Slope Formula---
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point


So lets use the Point-Slope Formula to find the equation of the line


y-13=%2813%2F16%29%28x-18%29 Plug in m=13%2F16, x%5B1%5D=18, and y%5B1%5D=13 (these values are given)


y-13=%2813%2F16%29x%2B%2813%2F16%29%28-18%29 Distribute 13%2F16


y-13=%2813%2F16%29x-117%2F8 Multiply 13%2F16 and -18 to get -117%2F8


y=%2813%2F16%29x-117%2F8%2B13 Add 13 to both sides to isolate y


y=%2813%2F16%29x-13%2F8 Combine like terms -117%2F8 and 13 to get -13%2F8 (note: if you need help with combining fractions, check out this solver)


------------------------------------------------------------------------------------------------------------
Answer:


So the equation of the line with a slope of 13%2F16 which goes through the point (18,13) is:


y=%2813%2F16%29x-13%2F8 which is now in y=mx%2Bb form where the slope is m=13%2F16 and the y-intercept is b=-13%2F8