Question 217318:  The third term of an arithmetic sequence is 4 and the sum of the first 8 term is 36. Write down the first 8 term of the sequence.  
 
 Answer by drj(1380)      (Show Source): 
You can  put this solution on YOUR website! The third term of an arithmetic sequence is 4 and the sum of the first 8 term is 36. Write down the first 8 term of the sequence. 
 
 
Step 1.  An arithmetic sequence goes from one term to the next by always adding (or subtracting) the same value 
 
 
Step 2.  Let x be the number to add or subtract in the sequence.
 
 
Step 3.  Let a be the first term, let a+x be the second term, let a+2x be the third term, a+3x be the fourth term, and a+(n-1)x be the nth term
 
 
Step 4.  Let a+7x be the 8th term.   Then the sum of the first and eighth term is a+a+7x=2a+7x.  The sum of the second term and seventh term is the a+x+a+6x=2a+6x.  So four the first eight terms, there will be four pairs of 2a+6x which will equal to 36 or
 
 
 
 
 
   Equation A
 
 
Also   Equation B since the 3th term is 4.
 
 
Step 5.  Then we have a system of equations given as Equations A and B.  The following steps will solve the equation by substitution.
 
 
 | Solved by pluggable solver: SOLVE linear system by SUBSTITUTION |  
Solve: 
   We'll use substitution. After moving 7*x to the right, we get: 
   , or  . Substitute that 
  into another equation: 
    and simplify: So, we know that x=0.333333333333333. Since  , a=3.33333333333333. 
   
  Answer:  . 
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So a=  and x= 
 
 
So sequence is:   ,  ,  ,  ,  ,  ,  ,  .
 
 
Check:  The third term is   and the sum is   
 
 
Step 6.   ANSWER:  The sequence is  ,  ,  ,  ,  ,  ,  ,  .
 
 
I hope the above steps and explanation were helpful. 
 
 
For Step-By-Step videos on Introduction to Algebra, 
 
please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and 
 
for Trigonometry please visit 
 
http://www.FreedomUniversity.TV/courses/Trigonometry. 
 
 
Also, good luck in your studies and contact me at 
 
john@e-liteworks.com for your future math needs.
 
 
Respectfully,  
Dr J
 
 
 
 
 
 
 
 
 
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