SOLUTION: Three times the sum of twice a number and five is equal to five less than the number. What is the number?

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Question 217303: Three times the sum of twice a number and five is equal to five less than the number. What is the number?
Found 2 solutions by RAY100, drj:
Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
Let n= number
.
3*(2n+5) = n-5
.
6n + 15 = n-5
.
5n = -20
.
n= -4
.
.
check,,,3*-3 = -9,,,,,ok
.

Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
Three times the sum of twice a number and five is equal to five less than the number. What is the number?

Step 1. Let n be the number.

Step 2. Let 2n+5 be the sum of twice a number and five

Step 3. Let 3(2n+5) be three times the sum of twice a number and five

Step 4 Let n-5 be five less than the number.

Step 5. Then using Steps 3 and 4, we have 3%282n%2B5%29=n-5 since three times the sum of twice a number and five is equal to five less than the number.

Step 6. Solving the equation in Step 5 yields the following steps:

3%282n%2B5%29=n-5

6n%2B15=n-5

Add -n-15 to both sides of the equation

6n%2B15-n-15=n-5-n-15

5n=-20

Divide 5 to both sides of the equation

5n%2F5=-20%2F5

n=-4

Check if equation in Step 5 is true...3%282n%2B5%29=n-5 or 3%282%2A%28-4%29%2B5%29=-4-5 that yields 3%2A%28-8%2B5%29=-4-5...which is a true statement.

I hope the above steps and explanation were helpful.

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Also, good luck in your studies and contact me at
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Respectfully,
Dr J