SOLUTION: How many Liters of a 40% solution and a 16% solution must be mixed to obtain 20 liters of a 22% solution? from there i got the equation .4x + .16(20-x)= 20(.22)
from .4x+ .16
Algebra ->
Customizable Word Problem Solvers
-> Numbers
-> SOLUTION: How many Liters of a 40% solution and a 16% solution must be mixed to obtain 20 liters of a 22% solution? from there i got the equation .4x + .16(20-x)= 20(.22)
from .4x+ .16
Log On
Question 217281: How many Liters of a 40% solution and a 16% solution must be mixed to obtain 20 liters of a 22% solution? from there i got the equation .4x + .16(20-x)= 20(.22)
from .4x+ .16(20-x)= 20 (.22) how is the answer x=5 and is 5 liters at 40% and 15 liters at 16%
need a break down of how to get x=5, 5 liters at 40 %, and 15 liters at 16% Answer by rfer(16322) (Show Source):
(